# Ohms law calculator
**URL:** https://forum.makecode.com/t/ohms-law-calculator/26315
**Category:** Arcade
**Created:** [January 25, 2024, 1:59am UTC](https://forum.makecode.com/t/ohms-law-calculator/26315 "2024-01-25T01:59:38Z")
**Posts on this page:** 2
**Page:** 1
### Author:  [@RobbyZero](https://forum.makecode.com/u/RobbyZero)
#### Post date: [January 25, 2024, 1:59am UTC](https://forum.makecode.com/t/ohms-law-calculator/26315/1 "2024-01-25T01:59:38Z")
Hey I had an hour of free time to myself and I made this
> **[Ohms Law Calculator](https://arcade.makecode.com/S08678-83143-47612-33122)**
>
> Made with ❤️ in Microsoft MakeCode Arcade.
Click B to pull up the menu again
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### Author:  [@RobbyZero](https://forum.makecode.com/u/RobbyZero)
#### Post date: [April 16, 2024, 3:42am UTC](https://forum.makecode.com/t/ohms-law-calculator/26315/2 "2024-04-16T03:42:11Z")
I just thought I’d go a little in depth about how this works. Basically if you’ve ever learned about what electrical engineering is you would know that you need to have a power supply, like a battery. You would also need a way to cut down the power by a little bit. That would be done with a resistor. The thing battery’s and resistors have in common is the measurement. They don’t use the exact same measurement but if you know what battery you need for a devise then you would know the **voltage**. Which is the measurement of battery’s. And the measurement of resistors is measured in **ohms**. The ohms law calculator uses two of the following four measurements to calculate the missing two. The measurements are: Ohms, Volts, Power, and Current. If you know the first two on your project than you could find out the other two using the ohms law wheel shown below.
Let’s say you have a **Power** _6_ and a **Voltage** of _12_.
(Just so you know **Amps** is another word for current)
By looking at the wheel you see to find the current you divide the **Power** by the **Volts**.
Tada 🎉 you have got a **Current** of _0.5_.
Now let’s find the **Ohms**.
By looking at this we can see that to find this we solve **Volts** to the 2nd power (or **Volts** squared) divided by the **Power** which is _24_
Now we know that the **Ohms** are _24_ and the **Current** is _0.5_. What this code does is basically all that bit without you doing the math.
I hope you understand what this is and how to use it now.
@RobbyZero